A)
[tex] \frac{ {5}^{4} }{ {25}^{2} } \\ =\frac{ {5}^{4} }{ ({5}^{2})^{2} } = \frac{ {5}^{4} }{ {5}^{4} } = 1[/tex]
B)
[tex] \frac{ {a}^{3} {b}^{ - 2} }{ab} = \frac{ {a}^{3 - 1} }{ {b}^{2 + 1} } = \frac{ {a}^{2} }{ {b}^{3} } = {a}^{2} {b}^{ - 3} [/tex]
Semoga membantu!
Penjelasan dengan langkah-langkah:
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Sederhanakan dan hitung soal berikut
Soal bagian A
[tex]\displaystyle \sf \frac{5^4}{25^2}[/tex]
[tex]= \displaystyle \sf \frac{5^4}{(5^2)^2}[/tex]
[tex]= \displaystyle \sf \frac{5^4}{5^{2 \times 2}}[/tex]
[tex]= \displaystyle \frac{\cancel{5^4}}{\cancel{5^4}}[/tex]
[tex]= \sf 1[/tex]
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Soal bagian B
[tex]\displaystyle \sf \frac{a^3 b^{-2}}{ab}[/tex]
[tex]= \displaystyle \sf \frac{a^{\cancel{3}} b^{-2}}{\cancel{a} b}[/tex]
[tex]= \displaystyle \sf \frac{a^2}{b^{1-(-2)}}[/tex]
[tex]= \displaystyle \sf \frac{a^2}{b^{1+2}}[/tex]
[tex] = \displaystyle \sf \frac{a^2}{b^3}[/tex]
[answer.2.content]
